0=-5x^2-405

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Solution for 0=-5x^2-405 equation: 



0=-5x^2-405

We move all terms to the left:

0-(-5x^2-405)=0

We add all the numbers together, and all the variables

-(-5x^2-405)=0

We get rid of parentheses

5x^2+405=0

a = 5; b = 0; c = +405;
Δ = b2-4ac
Δ = 02-4·5·405
Δ = -8100
Delta is less than zero, so there is no solution for the equation

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